未验证 提交 9971f981 编写于 作者: F fpringle 提交者: GitHub

Added solution for Project Euler problem 87. (#3141)

* Added solution for Project Euler problem 87. Fixes: #2695

* Update docstring and 0-padding in directory name. Reference: #3256
上级 a1e9656e
"""
Project Euler Problem 87: https://projecteuler.net/problem=87
The smallest number expressible as the sum of a prime square, prime cube, and prime
fourth power is 28. In fact, there are exactly four numbers below fifty that can be
expressed in such a way:
28 = 22 + 23 + 24
33 = 32 + 23 + 24
49 = 52 + 23 + 24
47 = 22 + 33 + 24
How many numbers below fifty million can be expressed as the sum of a prime square,
prime cube, and prime fourth power?
"""
def solution(limit: int = 50000000) -> int:
"""
Return the number of integers less than limit which can be expressed as the sum
of a prime square, prime cube, and prime fourth power.
>>> solution(50)
4
"""
ret = set()
prime_square_limit = int((limit - 24) ** (1 / 2))
primes = set(range(3, prime_square_limit + 1, 2))
primes.add(2)
for p in range(3, prime_square_limit + 1, 2):
if p not in primes:
continue
primes.difference_update(set(range(p * p, prime_square_limit + 1, p)))
for prime1 in primes:
square = prime1 * prime1
for prime2 in primes:
cube = prime2 * prime2 * prime2
if square + cube >= limit - 16:
break
for prime3 in primes:
tetr = prime3 * prime3 * prime3 * prime3
total = square + cube + tetr
if total >= limit:
break
ret.add(total)
return len(ret)
if __name__ == "__main__":
print(f"{solution() = }")
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