未验证 提交 406ad387 编写于 作者: S Sushil Kumar 提交者: GitHub

Suggested changes has been made.

上级 0d61b049
/**
* \file
* \brief [Median search](https://en.wikipedia.org/wiki/Median_search) algorithm
* cases from [here](https://brilliant.org/wiki/median-finding-algorithm/)
* \ingroup median search
*/
// Given an array A[1,...,n] of n numbers and an index idx, idx, where 1≤idx≤ n, 1≤idx≤ n, find the i-th smallest element of A.
#include <iostream>
#include <algorithm>
#include <vector>
/**
* @namespace search
* @brief Search algorithms
*/
namespace search {
/**
* @namespace median_search
* @brief Functions for [Median search](https://en.wikipedia.org/wiki/Median_search) algorithm
* @cases from [here](https://brilliant.org/wiki/median-finding-algorithm/)
*/
namespace median_search {
/* Assume that all the elements of A are distinct
def median_of_medians(A, i):
......@@ -43,8 +49,8 @@
* print median_of_medians(B,4) #should be 5
*/
int median_of_medians(std::vector<int> a, int idx){
int pivot = 0; // initialized with zero
int median_of_medians(std::vector<int> a, int idx){ // Search the element in **a** whose index is **idx** and return element at index **idx** in **a** (a[idx])
int pivot = 0; // initialized with zero
std::vector<int> m;
int r = a.size();
for(int i = 0; i < r; i += 5){
......@@ -81,9 +87,12 @@ int median_of_medians(std::vector<int> a, int idx){
return pivot;
}
}
} // namespace median_search
} // namespace search
/* Main function*/
/**
* Main function
*/
int main()
{
int n = 0;
......@@ -95,9 +104,9 @@ int main()
std::cin >> a[i];
}
std::cout << "Median: "; // Median defination: https://en.wikipedia.org/wiki/Median
int x = median_of_medians(a, (n - 1) / 2);
int x = search::median_search::median_of_medians(a, (n - 1) / 2);
if(n % 2 == 0){
int y = median_of_medians(a, n / 2);
int y = search::median_search::median_of_medians(a, n / 2);
std::cout << (float(x) + float(y))/2.0;
}
else{
......@@ -108,7 +117,7 @@ int main()
int idx = 0;
std::cin >> idx;
idx--;
std::cout << idx + 1<< "-th smallest element: " << median_of_medians(a, idx) << '\n';
std::cout << idx + 1<< "-th smallest element: " << search::median_search::median_of_medians(a, idx) << '\n';
return 0;
}
Markdown is supported
0% .
You are about to add 0 people to the discussion. Proceed with caution.
先完成此消息的编辑!
想要评论请 注册