提交 80d89e6a 编写于 作者: B Bodo Möller

Sign-related fixes (and tests).

BN_mod_exp_mont does not work properly yet if modulus m
is negative (we want computations to be carried out
modulo |m|).
上级 bc5f2740
......@@ -3,6 +3,10 @@
Changes between 0.9.6 and 0.9.7 [xx XXX 2000]
*) BN_div bugfix: If the result is 0, the sign (res->neg) must not be
set.
[Bodo Moeller]
*) Changed the LHASH code to use prototypes for callbacks, and created
macros to declare and implement thin (optionally static) functions
that provide type-safety and avoid function pointer casting for the
......
......@@ -241,6 +241,8 @@ int BN_div(BIGNUM *dv, BIGNUM *rm, const BIGNUM *num, const BIGNUM *divisor,
}
else
res->top--;
if (res->top == 0)
res->neg = 0;
resp--;
for (i=0; i<loop-1; i++)
......
......@@ -133,21 +133,16 @@ BIGNUM *BN_mod_sqrt(BIGNUM *in, const BIGNUM *a, const BIGNUM *p, BN_CTX *ctx)
e = 1;
while (!BN_is_bit_set(p, e))
e++;
if (e > 2)
{
/* we don't need this q if e = 1 or 2 */
if (!BN_rshift(q, p, e)) goto end;
q->neg = 0;
}
/* we'll set q later (if needed) */
if (e == 1)
{
/* The easy case: (p-1)/2 is odd, so 2 has an inverse
* modulo (p-1)/2, and square roots can be computed
/* The easy case: (|p|-1)/2 is odd, so 2 has an inverse
* modulo (|p|-1)/2, and square roots can be computed
* directly by modular exponentiation.
* We have
* 2 * (p+1)/4 == 1 (mod (p-1)/2),
* so we can use exponent (p+1)/4, i.e. (p-3)/4 + 1.
* 2 * (|p|+1)/4 == 1 (mod (|p|-1)/2),
* so we can use exponent (|p|+1)/4, i.e. (|p|-3)/4 + 1.
*/
if (!BN_rshift(q, p, 2)) goto end;
q->neg = 0;
......@@ -159,16 +154,16 @@ BIGNUM *BN_mod_sqrt(BIGNUM *in, const BIGNUM *a, const BIGNUM *p, BN_CTX *ctx)
if (e == 2)
{
/* p == 5 (mod 8)
/* |p| == 5 (mod 8)
*
* In this case 2 is always a non-square since
* Legendre(2,p) = (-1)^((p^2-1)/8) for any odd prime.
* So if a really is a square, then 2*a is a non-square.
* Thus for
* b := (2*a)^((p-5)/8),
* b := (2*a)^((|p|-5)/8),
* i := (2*a)*b^2
* we have
* i^2 = (2*a)^((1 + (p-5)/4)*2)
* i^2 = (2*a)^((1 + (|p|-5)/4)*2)
* = (2*a)^((p-1)/2)
* = -1;
* so if we set
......@@ -195,7 +190,7 @@ BIGNUM *BN_mod_sqrt(BIGNUM *in, const BIGNUM *a, const BIGNUM *p, BN_CTX *ctx)
/* t := 2*a */
if (!BN_mod_lshift1_quick(t, a, p)) goto end;
/* b := (2*a)^((p-5)/8) */
/* b := (2*a)^((|p|-5)/8) */
if (!BN_rshift(q, p, 3)) goto end;
q->neg = 0;
if (!BN_mod_exp(b, t, q, p, ctx)) goto end;
......@@ -218,6 +213,8 @@ BIGNUM *BN_mod_sqrt(BIGNUM *in, const BIGNUM *a, const BIGNUM *p, BN_CTX *ctx)
/* e > 2, so we really have to use the Tonelli/Shanks algorithm.
* First, find some y that is not a square. */
if (!BN_copy(q, p)) goto end; /* use 'q' as temp */
q->neg = 0;
i = 2;
do
{
......@@ -240,7 +237,7 @@ BIGNUM *BN_mod_sqrt(BIGNUM *in, const BIGNUM *a, const BIGNUM *p, BN_CTX *ctx)
if (!BN_set_word(y, i)) goto end;
}
r = BN_kronecker(y, p, ctx);
r = BN_kronecker(y, q, ctx); /* here 'q' is |p| */
if (r < -1) goto end;
if (r == 0)
{
......@@ -262,6 +259,8 @@ BIGNUM *BN_mod_sqrt(BIGNUM *in, const BIGNUM *a, const BIGNUM *p, BN_CTX *ctx)
goto end;
}
/* Here's our actual 'q': */
if (!BN_rshift(q, q, e)) goto end;
/* Now that we have some non-square, we can find an element
* of order 2^e by computing its q'th power. */
......
......@@ -907,6 +907,7 @@ int test_kron(BIO *bp, BN_CTX *ctx)
* works.) */
if (!BN_generate_prime(b, 512, 0, NULL, NULL, genprime_cb, NULL)) goto err;
b->neg = rand_neg();
putc('\n', stderr);
for (i = 0; i < num0; i++)
......@@ -914,12 +915,17 @@ int test_kron(BIO *bp, BN_CTX *ctx)
if (!BN_bntest_rand(a, 512, 0, 0)) goto err;
a->neg = rand_neg();
/* t := (b-1)/2 (note that b is odd) */
/* t := (|b|-1)/2 (note that b is odd) */
if (!BN_copy(t, b)) goto err;
t->neg = 0;
if (!BN_sub_word(t, 1)) goto err;
if (!BN_rshift1(t, t)) goto err;
/* r := a^t mod b */
if (!BN_mod_exp(r, a, t, b, ctx)) goto err;
/* FIXME: Using BN_mod_exp (Montgomery variant) leads to
* incorrect results if b is negative ("Legendre symbol
* computation failed").
* We want computations to be carried out modulo |b|. */
if (!BN_mod_exp_simple(r, a, t, b, ctx)) goto err;
if (BN_is_word(r, 1))
legendre = 1;
......@@ -938,6 +944,9 @@ int test_kron(BIO *bp, BN_CTX *ctx)
kronecker = BN_kronecker(a, b, ctx);
if (kronecker < -1) goto err;
/* we actually need BN_kronecker(a, |b|) */
if (a->neg && b->neg)
kronecker = -kronecker;
if (legendre != kronecker)
{
......@@ -991,6 +1000,7 @@ int test_sqrt(BIO *bp, BN_CTX *ctx)
if (!BN_generate_prime(p, 256, 0, a, r, genprime_cb, NULL)) goto err;
putc('\n', stderr);
}
p->neg = rand_neg();
for (j = 0; j < num2; j++)
{
......@@ -1003,6 +1013,8 @@ int test_sqrt(BIO *bp, BN_CTX *ctx)
if (!BN_nnmod(a, a, p, ctx)) goto err;
if (!BN_mod_sqr(a, a, p, ctx)) goto err;
if (!BN_mul(a, a, r, ctx)) goto err;
if (rand_neg())
if (!BN_sub(a, a, p)) goto err;
if (!BN_mod_sqrt(r, a, p, ctx)) goto err;
if (!BN_mod_sqr(r, r, p, ctx)) goto err;
......
Markdown is supported
0% .
You are about to add 0 people to the discussion. Proceed with caution.
先完成此消息的编辑!
想要评论请 注册