add ask ipynb file

001-install.ipynb

@@ -478,21 +478,17 @@
  ],
  "metadata": {
   "kernelspec": {
-   "display_name": "Python 3 (ipykernel)",
-   "language": "python",
-   "name": "python3"
+   "display_name": "Java",
+   "language": "java",
+   "name": "java"
   },
   "language_info": {
-   "codemirror_mode": {
-    "name": "ipython",
-    "version": 3
-   },
-   "file_extension": ".py",
-   "mimetype": "text/x-python",
-   "name": "python",
-   "nbconvert_exporter": "python",
-   "pygments_lexer": "ipython3",
-   "version": "3.9.1"
+   "codemirror_mode": "java",
+   "file_extension": ".jshell",
+   "mimetype": "text/x-java-source",
+   "name": "Java",
+   "pygments_lexer": "java",
+   "version": "16.0.1+9-24"
   },
   "toc-showtags": false
  },

7478975/53472024.ipynb

+{
+ "cells": [
+  {
+   "cell_type": "markdown",
+   "id": "7a4943a4-34f0-4195-bd2c-9b1eb945ef21",
+   "metadata": {},
+   "source": [
+    "## 两个列表如何相互匹配？\n",
+    "\n",
+    "a=['good' , 'study' , 'day' , 'up']\n",
+    "b=[0 , 1 , 1 , 0]\n",
+    "c=['study' , 'day']\n",
+    "\n",
+    "要求：当 b[i] == 1时，提取出 a[i] ，并组成新列表c\n",
+    "\n",
+    "在**不使用循环遍历**的前提下，有没有一个函数能直接做到？"
+   ]
+  },
+  {
+   "cell_type": "code",
+   "execution_count": 25,
+   "id": "df926d1a-23d8-4484-a56e-33f00e84e727",
+   "metadata": {},
+   "outputs": [
+    {
+     "name": "stdout",
+     "output_type": "stream",
+     "text": [
+      "['good', 'study', 'day', 'up']\n",
+      "[0, 1, 1, 0]\n",
+      "['null']\n"
+     ]
+    }
+   ],
+   "source": [
+    "# Step1：初始化数据\n",
+    "# 执行代码请按 Ctrl / Control + Enter\n",
+    "a=['good' , 'study' , 'day' , 'up']\n",
+    "b=[0 , 1 , 1 , 0]\n",
+    "c=['null']\n",
+    "print(a)\n",
+    "print(b)\n",
+    "print(c)"
+   ]
+  },
+  {
+   "cell_type": "code",
+   "execution_count": 26,
+   "id": "139123a6-0dc0-4c53-8a1e-79d132601887",
+   "metadata": {},
+   "outputs": [
+    {
+     "name": "stdout",
+     "output_type": "stream",
+     "text": [
+      "['study', 'day']\n"
+     ]
+    }
+   ],
+   "source": [
+    "# Step2: 组成新列表c 并打印\n",
+    "# 回答作者 @yakumosumi\n",
+    "# 回答时间 2021-07-23 15:00\n",
+    "# 回答链接 https://ask.csdn.net/questions/7478975?spm=1005.2026.3001.5703&answer=53472024\n",
+    "# 作者描述 @yakumosumi 直接列表解析\n",
+    "# 执行代码请按 Shift + Enter\n",
+    "c = [a[i] for i in range(len(a)) if b[i] == 1]\n",
+    "print(c)"
+   ]
+  }
+ ],
+ "metadata": {
+  "kernelspec": {
+   "display_name": "Python 3 (ipykernel)",
+   "language": "python",
+   "name": "python3"
+  },
+  "language_info": {
+   "codemirror_mode": {
+    "name": "ipython",
+    "version": 3
+   },
+   "file_extension": ".py",
+   "mimetype": "text/x-python",
+   "name": "python",
+   "nbconvert_exporter": "python",
+   "pygments_lexer": "ipython3",
+   "version": "3.9.1"
+  }
+ },
+ "nbformat": 4,
+ "nbformat_minor": 5
+}