提交 badd4e0e 编写于 作者: L luzhipeng

feat: #334

上级 aac59ff7
......@@ -123,6 +123,7 @@ leetcode 题解,记录自己的 leetcode 解题之路。
- [240.search-a-2-d-matrix-ii](./problems/240.search-a-2-d-matrix-ii.md)
- 🖊 [279.perfect-squares](./problems/279.perfect-squares.md)
- [322.coin-change](./problems/322.coin-change.md)
- 🆕 [334.increasing-triplet-subsequence](./problems/334.increasing-triplet-subsequence.md)
- [328.odd-even-linked-list](./problems/328.odd-even-linked-list.md)
- [416.partition-equal-subset-sum](./problems/416.partition-equal-subset-sum.md)
- [445.add-two-numbers-ii](./problems/445.add-two-numbers-ii.md)
......
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......@@ -51,7 +51,7 @@ var maxProduct = function(nums) {
![152.maximum-product-subarray](../assets/problems/152.maximum-product-subarray.png)
这种思路的解法由于只需要遍历次,其时间复杂度是O(n),代码见下方代码区。
这种思路的解法由于只需要遍历次,其时间复杂度是O(n),代码见下方代码区。
## 关键点
- 同时记录乘积最大值和乘积最小值
......
## 题目地址
https://leetcode.com/problems/increasing-triplet-subsequence/description/
## 题目描述
```
Given an unsorted array return whether an increasing subsequence of length 3 exists or not in the array.
Formally the function should:
Return true if there exists i, j, k
such that arr[i] < arr[j] < arr[k] given 0 ≤ i < j < k ≤ n-1 else return false.
Note: Your algorithm should run in O(n) time complexity and O(1) space complexity.
Example 1:
Input: [1,2,3,4,5]
Output: true
Example 2:
Input: [5,4,3,2,1]
Output: false
```
## 思路
这道题是求解顺序数字是否有三个递增的排列, 注意这里没有要求连续的,因此诸如滑动窗口的思路是不可以的。
题目要求O(n)的时间复杂度和O(1)的空间复杂度,因此暴力的做法就不用考虑了。
我们的目标就是`依次`找到三个数字,其顺序是递增的。因此我们的做法可以是依次遍历,
然后维护三个变量,分别记录最小值,第二小值,第三小值。只要我们能够填满这三个变量就返回true,否则返回false。
![334.increasing-triplet-subsequence](../assets/problems/334.increasing-triplet-subsequence.png)
## 关键点解析
- 维护三个变量,分别记录最小值,第二小值,第三小值。只要我们能够填满这三个变量就返回true,否则返回false
## 代码
```js
/*
* @lc app=leetcode id=334 lang=javascript
*
......@@ -62,4 +103,4 @@ var increasingTriplet = function(nums) {
return false;
};
```
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