提交 1433ef22 编写于 作者: R Rp-sushil

[BUG] #804 search/median_search.cpp FIXED

上级 dfe5bd76
/**
* \file
* \brief [Median search](https://en.wikipedia.org/wiki/Median_search) algorithm
* \warning This core is erroneous and gives invorrect answers. Tested using
* cases from [here](https://brilliant.org/wiki/median-finding-algorithm/)
* \ingroup median search
* \{
*/
#include <algorithm>
#include <iostream>
#include <algorithm>
#include <vector>
using namespace std;
/**
* @todo add documentation
*/
template <class X>
void comp(X x, std::vector<int> *s1, std::vector<int> *s2,
std::vector<int> *s3) {
if (s1->size() >= x && s1->size() + s2->size() < x) {
std::cout << (*s2)[0] << " is the " << x + 1 << "th element from front";
} else if (s1->size() > x) {
std::sort(s1->begin(), s1->end());
std::cout << (*s1)[x] << " is the " << x + 1 << "th element from front";
} else if (s1->size() + s2->size() <= x && s3->size() > x) {
std::sort(s3->begin(), s3->end());
std::cout << (*s3)[x - s1->size() - s2->size()] << " is the " << x + 1
<< "th element from front";
} else {
std::cout << x + 1 << " is invalid location";
}
}
/* Assume that all the elements of A are distinct
def median_of_medians(A, i):
#define MAX_NUM 20 ///< maximum number of values to sort from
#divide A into sublists of len 5
sublists = [A[j:j+5] for j in range(0, len(A), 5)]
medians = [sorted(sublist)[len(sublist)/2] for sublist in sublists]
if len(medians) <= 5:
pivot = sorted(medians)[len(medians)/2]
else:
#the pivot is the median of the medians
pivot = median_of_medians(medians, len(medians)/2)
/**
* Main function
*/
int main() {
std::vector<int> v{25, 21, 98, 100, 76, 22, 43, 60, 89, 87};
std::vector<int> s1;
std::vector<int> s2;
std::vector<int> s3;
#partitioning step
low = [j for j in A if j < pivot]
high = [j for j in A if j > pivot]
// creates an array of random numbers
// for (int i = 0; i < MAX_NUM; i++) {
// int r = std::rand() % 1000;
// v.push_back(r);
// std::cout << r << " ";
// }
for (int r : v) std::cout << r << " ";
k = len(low)
if i < k:
return median_of_medians(low,i)
elif i > k:
return median_of_medians(high,i-k-1)
else: #pivot = k
return pivot
*/
int median = std::rand() % 1000; // initialize to a random numnber
/*
* Here are some example lists you can use to see how the algorithm works
* A = [1,2,3,4,5,1000,8,9,99] (Contain Unique Elements)
* B = [1,2,3,4,5,6] (Contains Unique Elements)
* print median_of_medians(A, 0) #should be 1
* print median_of_medians(A,7) #should be 99
* print median_of_medians(B,4) #should be 5
*/
std::cout << "\nmedian=" << median << std::endl;
int avg1, avg2, avg3, sum1 = 0, sum2 = 0, sum3 = 0;
int median_of_medians(vector<int> a, int idx){
int pivot;
vector<int> m;
int r = a.size();
for(int i = 0; i < r; i += 5){
sort(a.begin() + i, a.begin() + min(r, i + 5));
int mid = (i + min(r, i + 5)) / 2;
m.push_back(a[mid]);
}
int sz = int(m.size());
if(sz <= 5){
sort(m.begin(), m.end());
pivot = m[(sz- 1) / 2];
}
else{
pivot = median_of_medians(m, idx);
}
vector<int> low;
vector<int> high;
for(int i = 0; i < r; i++){
if(a[i] < pivot)
low.push_back(a[i]);
else if(a[i] > pivot)
high.push_back(a[i]);
}
int k = int(low.size());
if(idx < k)
return median_of_medians(low, idx);
else if(idx > k)
return median_of_medians(high, idx-k-1);
else
return pivot;
}
for (int i = 0; i < v.size(); i++) { // iterate through all numbers
if (v.back() == v[median]) {
avg1 = sum1 + v.back();
s2.push_back(v.back());
} else if (v.back() < v[median]) {
avg2 = sum2 + v.back();
s1.push_back(v.back());
} else {
avg3 = sum3 + v.back();
s3.push_back(v.back());
}
v.pop_back();
}
/* Main function*/
int x;
std::cout << "enter the no. to be searched form begining:- ";
std::cin >> x;
comp(x - 1, &s1, &s2, &s3);
int main()
{
int n;
cout << "Enter Size of Array: ";
cin >> n;
vector<int> a(n);
cout << "Enter Array: ";
for(int i = 0; i < n; i++)
cin >> a[i];
return 0;
cout << "Median: ";
int x = median_of_medians(a, (n - 1) / 2);
if(n % 2 == 0){
int y = median_of_medians(a, n / 2);
cout << (float(x) + float(y))/2.0;
}
else
cout << x;
cout << "\nTo find i-th smallest element ";
cout << "\nEnter i: ";
int idx;
cin >> idx;
idx--;
cout << "i-th smallest element: " << median_of_medians(a, idx) << endl;
return 0;
}
/// }
Markdown is supported
0% .
You are about to add 0 people to the discussion. Proceed with caution.
先完成此消息的编辑!
想要评论请 注册