未验证 提交 f308a05a 编写于 作者: A Ayaan Khan 提交者: GitHub

Merge pull request #1045 from Rp-sushil/rp

[BUG] #804 search/median_search.cpp FIXED
/**
* \file
* \brief [Median search](https://en.wikipedia.org/wiki/Median_search) algorithm
* \warning This core is erroneous and gives invorrect answers. Tested using
* cases from [here](https://brilliant.org/wiki/median-finding-algorithm/)
* \ingroup median search
* \{
* @file median_search.cpp
* @brief Implementation of [Median search](https://en.wikipedia.org/wiki/Median_of_medians) algorithm.
* @cases from [here](https://brilliant.org/wiki/median-finding-algorithm/)
*
* @details
* Given an array A[1,...,n] of n numbers and an index i, where 1 ≤ i ≤ n, find the i-th smallest element of A.
* median_of_medians(A, i):
* #divide A into sublists of len 5
* sublists = [A[j:j+5] for j in range(0, len(A), 5)]
* medians = [sorted(sublist)[len(sublist)/2] for sublist in sublists]
* if len(medians) <= 5:
* pivot = sorted(medians)[len(medians)/2]
* else:
* #the pivot is the median of the medians
* pivot = median_of_medians(medians, len(medians)/2)
* #partitioning step
* low = [j for j in A if j < pivot]
* high = [j for j in A if j > pivot]
* k = len(low)
* if i < k:
* return median_of_medians(low,i)
* elif i > k:
* return median_of_medians(high,i-k-1)
* else: #pivot = k
* return pivot
*
* \note this algorithm implements median search for only arrays which have distinct elements
*
* Here are some example lists you can use to see how the algorithm works
* A = [1,2,3,4,5,1000,8,9,99] (Contain Unique Elements)
* B = [1,2,3,4,5,6] (Contains Unique Elements)
* print median_of_medians(A, 0) #should be 1
* print median_of_medians(A,7) #should be 99
* print median_of_medians(B,4) #should be 5
*
* @author Unknown author
* @author [Sushil Kumar](https://github.com/Rp-sushil)
*/
#include <algorithm>
#include <iostream>
#include <algorithm>
#include <vector>
#include <cassert>
/**
* @todo add documentation
* @namespace search
* @brief Search algorithms
*/
namespace search {
/**
* @namespace median_search
* @brief Functions for [Median search](https://en.wikipedia.org/wiki/Median_search) algorithm
*/
template <class X>
void comp(X x, std::vector<int> *s1, std::vector<int> *s2,
std::vector<int> *s3) {
if (s1->size() >= x && s1->size() + s2->size() < x) {
std::cout << (*s2)[0] << " is the " << x + 1 << "th element from front";
} else if (s1->size() > x) {
std::sort(s1->begin(), s1->end());
std::cout << (*s1)[x] << " is the " << x + 1 << "th element from front";
} else if (s1->size() + s2->size() <= x && s3->size() > x) {
std::sort(s3->begin(), s3->end());
std::cout << (*s3)[x - s1->size() - s2->size()] << " is the " << x + 1
<< "th element from front";
} else {
std::cout << x + 1 << " is invalid location";
}
namespace median_search {
/**
* This function search the element in an array for the given index.
* @param A array where numbers are saved
* @param idx current index in array
* @returns corresponding element which we want to search.
*/
int median_of_medians(const std::vector<int>& A, const int& idx) {
int pivot = 0; // initialized with zero
std::vector<int> a(A.begin(), A.end());
std::vector<int> m;
int r = a.size();
for(int i = 0; i < r; i += 5){
std::sort(a.begin() + i, a.begin() + std::min(r, i + 5));
int mid = (i + std::min(r, i + 5)) / 2;
m.push_back(a[mid]);
}
int sz = int(m.size());
if(sz <= 5){
std::sort(m.begin(), m.end());
pivot = m[(sz- 1) / 2];
}
else{
pivot = median_of_medians(m, idx);
}
std::vector<int> low;
std::vector<int> high;
for(int i = 0; i < r; i++){
if(a[i] < pivot){
low.push_back(a[i]);
}
else if(a[i] > pivot){
high.push_back(a[i]);
}
}
int k = int(low.size());
if(idx < k){
return median_of_medians(low, idx);
}
else if(idx > k){
return median_of_medians(high, idx-k-1);
}
else{
return pivot;
}
}
} // namespace median_search
} // namespace search
#define MAX_NUM 20 ///< maximum number of values to sort from
/**
* Function to test above algorithm
*/
void test(){
std::vector<int> A{25,21,98,100,76,22,43,60,89,87};
int i = 3;
assert(A[6] == search::median_search::median_of_medians(A, i)); // A[6] = 43, is the fourth smallest element.
std::cout << "test case:1 passed\n";
std::vector<int> B{1,2,3,4,5,6};
int j = 4;
assert(B[4] == search::median_search::median_of_medians(B, j)); // B[4] = 5, is the fifth smallest element.
std::cout << "test case:2 passed\n";
std::vector<int> C{1,2,3,4,5,1000,8,9,99};
int k = 3;
assert(C[3] == search::median_search::median_of_medians(C, k)); // C[3] = 4, is the fourth smallest element.
std::cout << "test case:3 passed\n";
std::cout << "--All tests passed--\n";
}
/**
* Main function
*/
int main() {
std::vector<int> v{25, 21, 98, 100, 76, 22, 43, 60, 89, 87};
std::vector<int> s1;
std::vector<int> s2;
std::vector<int> s3;
// creates an array of random numbers
// for (int i = 0; i < MAX_NUM; i++) {
// int r = std::rand() % 1000;
// v.push_back(r);
// std::cout << r << " ";
// }
for (int r : v) std::cout << r << " ";
int median = std::rand() % 1000; // initialize to a random numnber
std::cout << "\nmedian=" << median << std::endl;
int avg1, avg2, avg3, sum1 = 0, sum2 = 0, sum3 = 0;
for (int i = 0; i < v.size(); i++) { // iterate through all numbers
if (v.back() == v[median]) {
avg1 = sum1 + v.back();
s2.push_back(v.back());
} else if (v.back() < v[median]) {
avg2 = sum2 + v.back();
s1.push_back(v.back());
} else {
avg3 = sum3 + v.back();
s3.push_back(v.back());
}
v.pop_back();
}
int x;
std::cout << "enter the no. to be searched form begining:- ";
std::cin >> x;
comp(x - 1, &s1, &s2, &s3);
return 0;
int main()
{
test();
int n = 0;
std::cout << "Enter Size of Array: ";
std::cin >> n;
std::vector<int> a(n);
std::cout << "Enter Array: ";
for(int i = 0; i < n; i++){
std::cin >> a[i];
}
std::cout << "Median: "; // Median defination: https://en.wikipedia.org/wiki/Median
int x = search::median_search::median_of_medians(a, (n - 1) / 2);
if(n % 2 == 0){
int y = search::median_search::median_of_medians(a, n / 2);
std::cout << (float(x) + float(y))/2.0;
}
else{
std::cout << x;
}
std::cout << "\nTo find i-th smallest element ";
std::cout << "\nEnter i: ";
int idx = 0;
std::cin >> idx;
idx--;
std::cout << idx + 1<< "-th smallest element: " << search::median_search::median_of_medians(a, idx) << '\n';
return 0;
}
/// }
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